[Dan Ebberts]

Try replacing the last line with this:

time < t2 ? ease(time,t1,t2,v1,v2) : ease(time,t3,t4,v2,v1);

[Dan Ebberts]

Well that’s a lot easier, and very do-able. Come back if you get stuck.

[Dan Ebberts]

That’s correct, but there are usually work-arounds. The most drastic one (which may be what you need) is for your expression to loop through all previous frames to re-calculate everything the expression has done on previous frames. The obvious downside is that the expression will eventually bog down because it has to do more and more calculations at each frame.

[Dan Ebberts]

I’m not sure exactly what you’re trying to do, but this should get you the value of the property with the expression at the previous frame:

valueAtTime(time-thisComp.frameDuration)

Remember though, this will be the pre-expression value, not the value calculated by the expression at the previous frame. I apologize if you already knew that.

[Dan Ebberts]

For any expression, value refers to the pre-expression, or keyframed value of the property. If the property has multiple dimensions, like scale or position, value is an array. So for scale, value[0] refers to the x value and value[1] refers to the y value. If you wanted the sliders to modify your keyframed value, you could do something like this:

x = effect("Slider Control")("Slider");
y = effect("Slider Control 2")("Slider");
[value[0]*x/100,value[1]*y/100]

[Dan Ebberts]

I’m not sure, but maybe like this:

if(thisComp.layer("subtitle").effect("Checkbox Control")("Checkbox").value){
  x = thisComp.layer("Effect").effect("Twiggle_Time")("Slider");
  y = thisComp.layer("Effect").effect("Twiggle_Value")("Slider");
  [x ,y];
}else
  value;

[Dan Ebberts]

I think this does what you want:

x = effect("Slider Control")("Slider");
y = effect("Slider Control 2")("Slider");
[x,y]

[Dan Ebberts]

Enter on the numeric keypad.

[Dan Ebberts]

As you’ve discovered, once you apply an expression to Source Text, all characters get the formatting of the first character. Unfortunately, that’s just how it works.

[Dan Ebberts]

I can’t think of any way to make the Wiggle Transform loop. You could apply this to the built-in shape specific Transform for Position to get a looping wiggle for x only:

freq = 1;
amp = 110;
loopTime = 3;
t = time % loopTime;
wiggle1 = wiggle(freq, amp, 1, 0.5, t);
wiggle2 = wiggle(freq, amp, 1, 0.5, t - loopTime);
w = linear(t, 0,  loopTime, wiggle1, wiggle2);
[w[0],value[1]]