[Dan Ebberts]

Maybe something like this:

w1 = thisComp.layer("Name").sourceRectAtTime().width;
w2 =thisComp.layer("Job tite").sourceRectAtTime().width;
Math.max(w1,w2)

[Dan Ebberts]

You just need to move a left paren in the last line, like this:

(comp("Build Comp").layer("ARTIST").text.sourceText.repeat(X) + "\n").repeat(Y)

[Dan Ebberts]

What do you mean exactly? It sounds like you have something in mind, but it’s not clear from your description.

[Dan Ebberts]

I can’t quite picture what you mean exactly.

[Dan Ebberts]

This should work:

(rotation%360).toFixed(0);

[Dan Ebberts]

% gives you the remainder of a division operation. So 10.5%3, for example, would give you 1.5

[Dan Ebberts]

I think this might be close to what you’re looking for:

m1 = thisLayer.marker.key(1).time;
m2 = thisLayer.marker.key(2).time;
pos1 = 0;
pos2 = 10;
d = m2 - m1;
offset = d - m1%d;
t = (time + offset)%d;
linear(t,0,d,pos1,pos2)

[Dan Ebberts]

This should work:

fadeDur = .5;
m = marker;
n = 0;
val = value;
if (m.numKeys == 1){
  t1 = m.key(1).time;
  val = ease(time,t1,t1+fadeDur,0,value);
}else if (m.numKeys > 1){
  t1 = m.key(1).time;
  t2 = m.key(2).time;
  if (time < t1 + fadeDur){
    val = ease(time,t1,t1+fadeDur,0,value);
  }else{
    val = ease(time,t2-fadeDur,t2,value,0);
  }
}

[Dan Ebberts]

This quick test worked for me:

app.project.activeItem.layer(1).property("ADBE Root Vectors Group").property("ADBE Vector Filter - Trim").property("ADBE Vector Trim Type").setValue(2);

[Dan Ebberts]

I still think it’s probably do-able, using the technique I described previously, but I fear it’s too complex to easily come up with a drop-in solution here, in this forum.