[Dan Ebberts]

No, an expression can only affect the property hosting the expression.

[Dan Ebberts]

Like this:

timeToFrames(inPoint)

[Dan Ebberts]

Andrei,

I’m not understanding what you mean by this:

>But if now I move my shape layer 2 seconds before

[Dan Ebberts]

Something like this maybe:

t = Math.max(time - inPoint,0);
(outPoint - inPoint - t).toFixed(1);

[Dan Ebberts]

<div>If you do that, you’re only checking the red channel. Maybe something like this:</div>

c = effect("Color Control")("Color").value;
if (c[0] == 1 && c[1] == 1 && c[2] == 1)
  999
else
  0

or this:

c = effect("Color Control")("Color").value;
white = [1,1,1,1];
if (JSON.stringify(c) == JSON.stringify(white))
  999
else
  0

Dan

[Dan Ebberts]

I’m guessing this isn’t exactly what you’re talking about, but it might give you some ideas:

flowerArray = [45, 135, 225, 315];
boxArray = [0, 90, 0, 90];
startFrame = 50;
endFrame = 100;
t1 = framesToTime(startFrame);
t2 = framesToTime(endFrame);
linear(time,t1,t2,flowerArray[index-1],boxArray[index-1]);

[Dan Ebberts]

In general, a position expression like this should give you a grid (it assumes every layer in the comp is participating):

w = 40;
h = 40;
numCols = 48;
origin = [w/2,h/2]
myCol = (index-1)%numCols;
myRow = Math.floor((index-1)/numCols);
origin + [myCol*w,myRow*h]

[Dan Ebberts]

value just says to use the keyframed/static value of the property. So in this case, it’s telling the expression not to do anything.

[Dan Ebberts]

Like this maybe:

if (thisComp.layer("subline").text.sourceText.length > 0) {
  value;
} else {
  [0,0];
}

[Dan Ebberts]

Try it this way:

if (thisComp.layer("subline").text.sourceText.length > 0) {
  value;
} else {
  0;
}