[Andrei Popa]

Make a text layer. Add this expression to the text property;


var numChars = 20;
var solution = '';
for(var i=0; i< numChars; i++){
solution+=Math.round(random())
}
solution


Andrei
My Envato portfolio.

[Andrei Popa]

Please be specific on what you want the script to do.

You want it to work only on video footage? Or maybe also on different layers?
Only on the active composition or the entire project?
And exactly like this one, treat them by the last 2 characters of the name?

Andrei
My Envato portfolio.

[Andrei Popa]

Off topic: Please don’t start your function name with capital letters.

On topic:

Idk if the problem is the one specified by Thomas. But if so, why don’t pass the composition as a parameter in your function?
Something like

function detect(comp) {
var videoLayer = comp.selectedLayers[0];
var time = comp.time;
var frame = Math.round(time / comp.frameDuration);
var opacityLevel = videoLayer.property("Transform").property("Opacity");
var threshold = 48.0;

above = false;
while (frame <= 100) {
t = frame * comp.frameDuration;
if (above) {
if (opacityLevel.valueAtTime(t, true) != threshold) {
frame++;
above = false;
}
} else if (opacityLevel.valueAtTime(t, true) == threshold) {
above = true;
var myMarker = new MarkerValue("Mark");
videoLayer.property("Marker").setValueAtTime(t, myMarker);
}
frame++;
}
}
//and call it like this on the onClick event of the button
detect(app.project.activeItem);


I need to see the entire code and test it in order to see the problem, because it’s not that obvious.
If you can share your code or file, I could be more explicit.

Andrei
My Envato portfolio.

[Andrei Popa]

I don’t have an Object.keys on my version of after effects. I use AE 2020.
It may be that you have a different version or maybe you have some sort of library that extendet “Object” with a .keys function. You can check that by either

alert(Object.toSource())

or

$.writeln(Object.toSource())

When i run either one of these 2 functions, i only get (function Object() { [native code] } ), which means that my Object class does not have any new functions added to it.

Andrei
My Envato portfolio.

[Andrei Popa]

I had a typo


var myFile = File.openDialog("Select your source file");
if (myFile != null && myFile.open("r")) {
var myString = myFile.read();
myFile.close();
}

var arrayOfFileNames = myString.split("\n");

for (var i = 0; i < arrayOfFileNames.length; i++) {
mySoundLayer = addFileToProject(new File(myFile.path + "/" + arrayOfFileNames[i]), app.project.activeItem);
mySoundLayer.startTime = i * 10;
}

function addFileToProject(myFile, myComp) {
var myImportOptions = new ImportOptions();
myImportOptions.file = myFile;
var fileAsItem = app.project.importFile(myImportOptions);
if (myComp != null) {
return myComp.layers.add(fileAsItem);
}
return fileAsItem;
}

Andrei
My Envato portfolio.

[Andrei Popa]

Haven’t test this but it should work. Run this with the target composition opened. Also, the sound files must be in the same folder as your text file.


var myFile = File.openDialog("Select your source file");
if (myFile != null && myFile.open("r")) {
var myString = myFile.read();
myFile.close();
}

var arrayOfFileNames = myString.split("\n");

for (var i = 0; i < arrayOfFileNames.length; i++) {
mySoundLayer = addFileToProject(new File(myFile.path + "/" + arrayOfFileNames[i]), aoo.project.activeItem);
mySoundLayer.startTime = i * 10;
}

function addFileToProject(myFile, myComp) {
var myImportOptions = new ImportOptions();
myImportOptions.file = myFile;
var fileAsItem = app.project.importFile(myImportOptions);
if (myComp != null) {
return myComp.layers.add(fileAsItem);
}
return fileAsItem;
}

Andrei
My Envato portfolio.

[Andrei Popa]

That is an object. An array looks like this myArray = [1,2,3] and you access its values like this myArray[1].
How do you want to get the values of your object? As a string in this format “1,2”? If yes, try this:

function getValues(object){
var values = [];
for (var i in object) {
values.push(object[i]);
}
return values.join(",");
}

alert(getValues(myArray));

Andrei
My Envato portfolio.

[Andrei Popa]

I think you also need to give it a value if the distance is greater.


target=thisComp.layer("Circle");
s = sub(target.transform.position,transform.position);
if(length(s) <= 100){
lookAt(target.transform.position,transform.position);
}else{
value
}


Andrei
My Envato portfolio.

[Andrei Popa]

Hey. I replaced pas with 0.1. Same result, but a lot heavier on rendering.
I use after effects 2020, 64 gigs of ram and Ryzen 7 3700x.
The layer is selected so you can see that it goes out of screen.

Andrei
My Envato portfolio.

[Andrei Popa]

I guess your only mistakes are the square brackets. You don’t need those, since the link to the color returns an array.

Col=thisComp.layer("Null 42").effect("Slider Control")("Slider");
color1=thisComp.layer("Null 42").effect("Color 1")("Color");
color2=thisComp.layer("Null 42").effect("Color 2")("Color");
linear (Col,0,100,color1,color2)

Andrei
My Envato portfolio.