How to use length in if statement

[tom ono]

Expression tells “undefined variable used in expression”
If there is not if statement,it works.
I used text source so that I make sure if length(s) was recognized.
Length(s) was recognised.

I want to know what is wrong. thanks.

target=thisComp.layer("circle");
s = sub(target.transform.position,transform.position);
if(length(s)<=100){
lookAt(target.transform.position,transform.position);
}


[Scott McGee]

I’m not sure what you are trying to do with the lookAt, as I’ve never used it before. But it works fine in text source.

target=thisComp.layer(“circle”);
s = sub(target.transform.position,transform.position);
if(length(s)>=100){
lookAt(target.transform.position,transform.position);
}

[Andrei Popa]

I think you also need to give it a value if the distance is greater.


target=thisComp.layer("Circle");
s = sub(target.transform.position,transform.position);
if(length(s) <= 100){
lookAt(target.transform.position,transform.position);
}else{
value
}


Andrei
My Envato portfolio.

[tom ono]

It works.
Thank you for giving me good advice.