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Changing Position keyframes but keeping the speed graph
I want to change the keyframe value of the position property if a certain condition is met
x = [100,200]; // my new keyframe1 value
y = [200, 300]; // my new keyframe2 value
If (n==1) // if true change the position keyframe1 and keyframe2
{
v1 = valueAtTime(key(1).time);
v2 = valueAtTime(key(2).time);
linear(time,key(1).time,key(2).time,x,y);
}
else value
This works for me but the above doesnt respect the speed graph. I have a speed graph set on the position, but when i run using the above expression the speed graph is ignored. Its runs in a linear fashion. How do i use both the expression as above and the speed graph.
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4 Replies
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I think this will only work correctly if the value of key 2 is bigger than the value of key 1
x = [100, 200]; // my new keyframe1 value
y = [200, 300]; // my new keyframe2 value
if(n == 1) // if true change the position keyframe1 and keyframe2
{
v1 = valueAtTime(key(1).time);
v2 = valueAtTime(key(2).time);
linear(value[0], v1[0], v2[0], x, y);
}
else value -
It’s a little tricky, but I think this will work in most situations:
newV1 = [100,200];
newV2 = [200,300];
if (numKeys > 1){
v1 = key(1).value;
v2 = key(numKeys).value;
t1 = key(1).time;
t2 = key(numKeys).time;
if (time < t1){
newV1;
}else if (time > t2){
newV2;
}else{
delta = v2 - v1;
newDelta = newV2 - newV1;
if (Math.abs(delta[0]) < .001){
x = v1[0];
}else{
x = newV1[0] + ((value[0] - v1[0])/delta[0])*(newDelta[0]);
}
if (Math.abs(delta[1]) < .001){
y = v1[1];
}else{
y = newV1[1] + ((value[1] - v1[1])/delta[1])*(newDelta[1]);
}
[x,y];
}
}else
value -
This surely works thank you.
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This also works. Im grateful for the response
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