Wow, very interesting approach, kind of what I was thinking of doing, knowing the width of every combination and then displaying it, but would have never done it so simple.
I’ve realized that after removing first letter and adding “…” at the end ends up being bigger than original text so I’ve added “+1” in expression of hidden layer, so it skips the output that has only on letter removed and dots added.
if(time<0)text.sourceText.substring(0, – timeToFrames(time)+1);
else value
Later I’ve realized that it skips 1st letter of every word in sentence.
Thanks a lot Andrei,
you’ve already helped me a ton!