[Roger Eaton]

I do not understand this specific example. I have variable names in a property Lead1, Lead2, Lead3 that are loaded from a color expression control. I then want my color to be one of those color control objects’ colors. A simple solution for me was to pick a random number between 1 and 6, and concatenate that number to the main variable name “Lead” and get …Lead5, which then in the final line of code gives the color. But I keep getting errors.

Defy1=thisComp.layer(“Colors”).effect(“Lead1”)(“Color”);
Defy2=thisComp.layer(“Colors”).effect(“Lead2”)(“Color”);
Defy3=thisComp.layer(“Colors”).effect(“Lead3”)(“Color”);
Defy4=thisComp.layer(“Colors”).effect(“Lead4”)(“Color”);
Defy5=thisComp.layer(“Colors”).effect(“Lead5”)(“Color”);
Defy6=thisComp.layer(“Colors”).effect(“Lead6”)(“Color”);
seedRandom(thisComp.layer(“Variables”).effect(“ParColorSeed”)(“Slider”),true);
ColorPic=random(1,6);
“Defy”+ColorPic //(also tried [“Defy”+ColorPic] with and without the quotes.

Is there a way to call the value of the concatenated variable name?

Thank you so much.

Roger Eaton

[Roger Eaton]

That was great. It worked perfectly for me (just ran across this thread). I have an additional question. I want the camera to orient in the direction of the path as it animates. (i.e. I will set the camera close to the level of the solid, tilt it to point “forward”, and want it to follow the animating stroke, twisting and turning. I’ve seen a tutorial (somewhere) on making an object orient with a path. Does it work the same with a camera?