concatenated strings as identifiers

[Dan Ebberts]

setting aside the concatenated strings and identifiers for a bit, at a higher level, what is it that you’re trying to accomplish?

Dan

[Chris Mcfall]

Hi Dan,first i just wanted to say i’m a big fan your site has been a real help to me since learning Expressions. 🙂 I have a comp (smoke) with a particle emitter nested inside another comp (text) inside the text comp there are several markers that trigger events (through a variety of expressions attached to a variety of properties) within both the text comp and the smoke comp. However this then needs to be nested inside another layer and there to be multiple instances running… of course each instance needs to reference its own text comp (renamed for each instance) Unfortunaly to do this would involve changing many tens of lines of code for each instance. Which would become work intensive… So instead I wanted to be able to reference a varible to a text layer (which i can then edit the contents of to match the layer that needs to be referenced) that would be inserted into a concatenated string that would create the identifier so that varible could be used throughout the code saving me LOTS of hard work… I hope i explained that ok…

[Dan Ebberts]

OK – I think I get it. I would think you’d point to the control layer like this:

L = comp(thisComp.layer(“SOURCE_LAYER”).text.sourceText).layer(“controlLayer”);
SmokeStartTime = L.marker.key(“STARTEMIT”).time;

Dan

[Chris Mcfall]

Thanks Dan, Sadly It didn’t allow me to reference the sourcetext it says
“comp() couldn’t find the comp named ‘TextProperty'” So i’m assuming its unable to read the value of the property… Though its not the end of te world I can just use the variable and change that each time. Although if you have any ideas it would be great to be able to reference source text. 🙂

[Dan Ebberts]

Ah. Sometimes you have to explicitly tell the expression engine to convert the sourceText to text. This should work:

L = comp(thisComp.layer(“SOURCE_LAYER”).text.sourceText.toString()).layer(“controlLayer”);
SmokeStartTime = L.marker.key(“STARTEMIT”).time;

Dan

[Chris Mcfall]

Mr Ebberts you are a coding super hero many thanks for your help.

[Roger Eaton]

I do not understand this specific example. I have variable names in a property Lead1, Lead2, Lead3 that are loaded from a color expression control. I then want my color to be one of those color control objects’ colors. A simple solution for me was to pick a random number between 1 and 6, and concatenate that number to the main variable name “Lead” and get …Lead5, which then in the final line of code gives the color. But I keep getting errors.

Defy1=thisComp.layer(“Colors”).effect(“Lead1”)(“Color”);
Defy2=thisComp.layer(“Colors”).effect(“Lead2”)(“Color”);
Defy3=thisComp.layer(“Colors”).effect(“Lead3”)(“Color”);
Defy4=thisComp.layer(“Colors”).effect(“Lead4”)(“Color”);
Defy5=thisComp.layer(“Colors”).effect(“Lead5”)(“Color”);
Defy6=thisComp.layer(“Colors”).effect(“Lead6”)(“Color”);
seedRandom(thisComp.layer(“Variables”).effect(“ParColorSeed”)(“Slider”),true);
ColorPic=random(1,6);
“Defy”+ColorPic //(also tried [“Defy”+ColorPic] with and without the quotes.

Is there a way to call the value of the concatenated variable name?

Thank you so much.

Roger Eaton

[Dan Ebberts]

I haven’t tested this, but I think I’d do it this way:

seedRandom(thisComp.layer(“Variables”).effect(“ParColorSeed”)(“Slider”),true);
ColorPic = Math.floor(random(6)) + 1;
thisComp.layer(“Colors”).effect(“Lead”+ColorPic)(“Color”);

Dan