Michael Tammaro
Forum Replies Created
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Michael Tammaro
November 11, 2015 at 8:37 pm in reply to: Creating Wave Interference Using After EffectsFinished product:
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Michael Tammaro
November 11, 2015 at 6:25 pm in reply to: Creating Wave Interference Using After EffectsI had trouble getting Wave World to behave properly, so I used the Radio Wave effect, and here’s how it looks when applied to the Caustics comp:
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Michael Tammaro
November 11, 2015 at 4:50 pm in reply to: Creating Wave Interference Using After EffectsHere’s what I have so far:
I basically have two compositions. The first contains a black solid on which I’ve applied the Wave World effect. On the other I’ve applied the Caustics effect and added the first composition and used it as the water surface. Very promising!
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Michael Tammaro
November 11, 2015 at 12:03 am in reply to: Creating Wave Interference Using After EffectsThank you both for your replies, and I like both of your suggestions.
This doesn’t have to look like water or realistic. The pattern of shadings is what’s important. Suppose, for example, light shading represents locations of constructive interference (where the wave is strong) and darker shading represents locations of destructive interference (where the wave is weak). There will be light shading, then, where the peaks of the individual waves overlap and dark shading where the peak of one wave overlaps a valley of the other. I was encouraged when I discovered the Wave World simulation effect, which has two “producers” that I can separate and adjust frequency, amplitude, etc. Then I could apply the effect to a solid layer, and maybe the Caustics effect might make it look like real water. The problem is that I can’t find a tutorial that shows me how to bring these elements together. I would probably benefit from leaning some basics about displacement maps and such things. I’ll keep tinkering and will also consider your suggestions.
Ken, I’ve tinkered with the radio wave effect, and I like your suggestion. I wonder, however, if it would produce the constructive/destructive areas correctly. I’ll have another try at it.
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Michael Tammaro
August 15, 2014 at 1:43 am in reply to: Debugging an expression (square root trouble?)Thanks so much, Dan. Initially I had written the expression out in word, then copied it into AE. I tried trying the expression directly into AE, using the default “-” on my keyboard, and the expression worked. I might not have tried that without your feedback, so thanks again.
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It has something to do with the square root, because I’m getting an error with this one too:
x0 = 1; y0 = 2; r1 = Math.sqrt((745 – x0)*(745 – x0) + (660 – y0)*(660 – y0)); x = r1 + x0; y =r1 + y0; [x,y]
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Excellent. Thanks.
Sorry to be so needy, but I’m getting a syntax error in the following expression:
x0 = 865; y0 = 525; r1 = Math.sqrt((745 – x0)*(745 – x0) + (660 – y0)*(660 – y0)); r2 = Math.sqrt((895 – x0)*(895 – x0) + (660 – y0)*(660 – y0)); o1 = thisComp.layer(“on1”).effect(“Slider Control”)(“Slider”); o2 = thisComp.layer(“on2”).effect(“Slider Control”)(“Slider”); l = thisComp.layer(“Wavel”).effect(“Slider Control”)(“Slider”); f = thisComp.layer(“Freq”).effect(“Slider Control”)(“Slider”); A = thisComp.layer(“Amp”).effect(“Slider Control”)(“Slider”); s1 = o1*A*Math.cos(2*Math.PI*r1/l – 2*Math.PI*f*time); s2 = o2*A*Math.cos(2*Math.PI*r1/l – 2*Math.PI*f*time); st1 = (x0 – 745)/r1; ct1 = (660 – y0)/r1; st2 = (x0 – 895)/r1; ct1 = (660 – y0)/r2; x = s1*st1 + s2*st2; y = s1*ct1 + s2*ct2; [x,y]
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Johnny, thank you!
If I have, say, 5 variables, do I need to create five null layers–one for each variable?