[Kyung Ko]

Yep, I figured. Thanks Tomas!

[Kyung Ko]

Thanks so much! This should work for my purpose. Really appreciate it!

[Kyung Ko]

Thank. you very much Alex for sharing great information.
I happened to lighten the functions by basically trying a bunch of different approaches but I didn’t know what exactly helped the situation. Your explanation helped me a lot to understand what could have been. I used to be a very design-oriented motion artist but recently I’ve been working on lots of customizable templates. I’m already taking your code and applying it to most of my functions. Learning every day! ☺ Thanks again!!

[Kyung Ko]

Hey Tomas, thanks so much for the clarification.
I kinda figured the second question I asked. I was basically asking if I can avoid the recalculation bt using inPoint when the value is fixed, but I figured it didn’t help, but limiting the range with the if statement helped.
I really appreciate your help!

[Kyung Ko]

Try this function…

function easeInOutQuad(t) { return t<.5 ? 2*t*t : -1+(4-2*t)*t };


[Kyung Ko]

I got your point and your code works with no issue. Thanks!

[Kyung Ko]

Try this…

freq = thisComp.layer("Your Layer").effect("Slider Control 1")("Slider");
amp = thisComp.layer("Your Layer").effect("Slider Control 2")("Slider");
wiggle(freq, amp)

[Kyung Ko]

Tomas, Thanks a lot for your input.

I have a few more questions.
1. Does it still calculate every single frame, even though you limit the loop or animation to happen only for one second at the beginning?
2. Are there any benefits using inPoint when the value at 0 seconds is the only needed value?
3. What if I use the if statement with time, so it outputs a fixed value after 1 second?
Any thoughts would be appreciated. Thanks a lot!

[Kyung Ko]

Sort of late reply, but HUGE THANKS to Dan!!
I’m learning a lot from you.

[Kyung Ko]

Thanks so much Dan!! This solved the problem I tried to get for hours.