[Jake Giddens]

Actually this might be what you’re looking for. I don’t know how good it is but it’s a free WYSIWYG web editor:

https://nvudev.com/index.php

The “Ice Cream Man“

[Jake Giddens]

I’ve heard good things about Dreamweaver although I’ve never used it. I’m not sure it’s cheap though. Something low budget would be like Microsoft FrontPage I suppose.

The “Ice Cream Man“

[Jake Giddens]

Ok I found out that that can’t be done.
Hmm… Ok how about this – is there a way I could include a variable in a new variables name?

Example

$number=”4″;

$image4=$file; //with “4” coming from the variable $number

The “Ice Cream Man“

[Jake Giddens]

Oh no. I’m sorry – that’s a real pain. Do you have to reconstruct your website from the ground up?

The “Ice Cream Man“

[Jake Giddens]

Abraham,

It displays a custom 500 error for me. Looks like it’s only temporarily down. Hope it comes back up for you soon.

The “Ice Cream Man“

[Jake Giddens]

Ah! Nevermind I was right the first time. I’ve gone mad.
I can’t simply echo it because it needs to go in this:

$theimage = getimagesize($dir/$image);

The “Ice Cream Man“

[Jake Giddens]

Right – only thing is I don’t need to echo $image. I just need to have it appear in another variable like this:

$display_image=”$dir/$image”;

And oh my God – wouldn’t you know it – I’ve overthought this one way too much. All I need to do is this:

echo “$dir/”;
echo $image;

Boy am I stupid. Sorry to have wasted your time with this.

Thank you for taking the time to help me out.

The “Ice Cream Man“

[Jake Giddens]

Sort of. And that would work except I need the output of the javscript, eg “cow.jpg” to be used in $image so that I can run the image through this:

//Gets the width and height of the image and outputs it as $theimage[0] (width) and $theimage[1]

(height)
$theimage = getimagesize($image);
$width = $theimage[0];
$height = $theimage[1];

like I said I think this can be done with a function() but I don’t know – I’m not very experienced with using function()

The “Ice Cream Man“

[Jake Giddens]

Yeah I’m using a reflection Javascript similar to that – it’s really awesome. I’ll look into the Ajax carousel. That should be a nice touch. Thank you very much.

Here’s one last question [hopefully :)] :

I made this javascript, which is printing a js array, a php variable (took out the “<"s so it would display): script type='text/javascript' document.write(photo[0]) /script I am then inserting that variable into another like this: $image="$dir/$java"; This is creative the link for the image. And of course it outputs the full javascript code instead of printing the array. My question is how do I get the array name to show? I'm thinking it must be done with a function() . . . The “Ice Cream Man“

[Jake Giddens]

Oh ok. Thanks I’ll have to check that out. By the way on the code you posted I keep getting this:

Fatal error: Call to undefined function imagecreatefromjpeg() in C:\Server\Apache2.2\htdocs\picrotate.php on line 7

Do you know what that’s all about?

thanks again.

The “Ice Cream Man“