[Dan Ebberts]

This is just a rough stab at it, without actually seeing what you’re doing, but I think it’s going to look something like this:

r = thisComp.layer("r_control").transform.rotation;
val = 0;
if (time >= r.key(2).time){
  n = Math.floor((time - r.key(2).time)/(r.key(4).time - r.key(2).time));
  t = (time - r.key(2).time)%(r.key(4).time - r.key(2).time);
  val = r.key(4).value*n + r.valueAtTime(t + r.key(2).time);
}
val

[Dan Ebberts]

There are a number of ways to set it up. This would probably be the most straightforward, brute-force method for the task as you’ve described it:

A = [0,0];
B = [500,200];
C = [1000,1000];
t1 = 0;
t2 = 2;
t3 = 4;
t4 = 6;
if (time < t3)
  linear(time,t1,t2,A,B)
else
  linear(time,t3,t4,B,C)

[Dan Ebberts]

I’m on Win 11, so it’s hard to say…

[Dan Ebberts]

I just tried it with this, and it seems to work:

var myColorPicker = $.colorPicker();
alert(myColorPicker.toString(16));

[Dan Ebberts]

It seems to work for me. Do you have a specific example?

[Dan Ebberts]

You could try a path expression like this:

delay = .1;
p0 = points(time);
iT0 = inTangents(time);
oT0 = outTangents(time);
for (i = 0; i < p0.length; i++){
  p = points(time - i*delay);
  p0[i] = p[i];
  iT = inTangents(time - i*delay);
  iT0[i] = iT[i];
  oT = outTangents(time - i*delay);
  oT0[i] = oT[i];
}
createPath(p0,iT0,oT0,isClosed())

[Dan Ebberts]

This should be close, I think:

sum = 0;
for (i = index+1; i <= thisComp.numLayers; i += 2){
  sum += thisComp.layer(i).effect("ADBE Slider Control")("ADBE Slider Control-0001");
}
sum + " %"

[Dan Ebberts]

You could try something like this:

(1/input.source.frameDuration).toFixed(2) + " fps"

[Dan Ebberts]

I think it would have to be done with a script, because expressions can’t toggle layer visibility or turn effects on and off (although I guess you could use expressions to control layer opacity and effect opacity in the effect’s compositing options). I’m guessing the script would need to be tailored to your specific workflow, but it sounds do-able (although I’m not familiar with CD4 “takes” so I’m not 100% sure).

[Dan Ebberts]

Try the expression I posted and see how it goes.