[Dan Ebberts]

Obviously I haven’t tested this, and I’m not even sure the syntax is exactly right, but it might give you an idea and get you headed in the right direction. This example is for Position:


n = thisLayer("Effects").numProperties;
accum = [0,0];
for (i = 1; i <= n; i++){
if (thisLayer("Effects").property(i).name.indexOf("PSR Offset") > -1){
accum += thisLayer("Effects").property(i).property("Position");
}
}
value + accum


Dan

[Dan Ebberts]

Try it this way:


if (numKeys > 1){
t1 = key(1).time;
t2 = key(2).time;
t3 = key(3).time;
t4 = key(4).time;
v1 = 100;
v2 = effect("Slider1")("Slider");
v3 = effect("Slider2")("Slider");
v4 = 100;
if (time < t2)
linear(time,t1,t2,v1,v2)
else if (time < t3)
linear(time,t2,t3,v2,v3)
else
linear(time,t3,t4,v3,v4);
}else
value


Dan

[Dan Ebberts]

For one thing, you were using the code that finds the most recent, previous marker, not the nearest marker. The dead giveaway is this line:

if (thisLayer.marker.key(n).time > time) n–;

You do that if you want to trigger something at the most recent, previous marker, not if you want to center your action around the nearest marker.

Dan

[Dan Ebberts]

This should work:


n = 0;
fadeFrames = 30;
tFade = framesToTime(fadeFrames)/2;

if (marker.numKeys > 0){
t = marker.nearestKey(time).time;
if (time < t)
ease (time, t-tFade, t, 100, 0)
else
ease (time, t, t+tFade, 0, 100);
}else
value


Dan

[Dan Ebberts]

Just ignore the numbers and use the names in the scripting guide, like this, and it will work out the way you want:

var pvt = myProperty.propertyValueType;
if (pvt == PropertyValueType.OneD || pvt == PropertyValueType.TwoD || etc…){
// do something
}

Dan

[Dan Ebberts]

This might be helpful:

https://www.motionscript.com/articles/speed-control.html#wiggle

Dan

[Dan Ebberts]

If this is tied into your previous question, it would probably be like this:

splitName = name.split(“_”);
tEnd = framesToTime(parseInt(splitName[2],10));
linear(time,tEnd,tEnd+2,100,0)

Dan

[Dan Ebberts]

The only way I know of is to duplicate the layer and delete the original.

Dan

[Dan Ebberts]

Not possible, as far as I know.

Dan

[Dan Ebberts]

Probably something close to this:

splitName = name.split(“_”);
tStart = framesToTime(parseInt(splitName[1],10));
tEnd = framesToTime(parseInt(splitName[2],10));
linear(time,tStart,tEnd,0,100)

Dan