[Dan Ebberts]

Something like this:

factor = .5;
x = Math.round(time*time*factor);
Math.pow(2,x)

factor determines how fast in counts.

Dan

[Dan Ebberts]

Assumptions: The flower that animates is named “master” and your scaling is uniform. Apply this scale expression to the other flowers:

s = thisComp.layer(“master”).scale;
value*s[0]/s.valueAtTime(0)[0]

Dan

[Dan Ebberts]

Assumptions: The flower that animates is named “master” and your scaling is uniform. Apply this scale expression to the other flowers:

s = thisComp.layer(“master”).scale;
value*s[0]/s.valueAtTime(0)[0]

Dan

[Dan Ebberts]

See the 10/7 thread “expression with springs”.

Dan

[Dan Ebberts]

See the 10/7 thread “expression with springs”.

Dan

[Dan Ebberts]

myLayer.startTime = 0;

Dan

[Dan Ebberts]

Conoa Easy Shapes or Boris Continuum would work.

Dan

[Dan Ebberts]

Corner Pin?

Dan

[Dan Ebberts]

You know, I just remebered that I had a brute-force method of doing the MM spring thing with expressions. It has to loop through the entire time line on every frame so it will undoubtedly bog down in long comps, but here it is:

restLength = 20; //rest length (pixels)
damp = .95;
leader = thisComp.layer(“leader”);

fDur = thisComp.frameDuration;
currFrame = Math.round(time/fDur);

p2 = position.valueAtTime(0);
v2 = 0;
for (f = 0; f <= currFrame; f++){ t = f*fDur; p1 = leader.position.valueAtTime(t); delta = p2 - p1; nDelta = normalize(delta); a = 2*nDelta*(length(delta) - restLength)*fDur; v2 = (v2 - a)*damp; p2 += v2; } p2 Dan

[Dan Ebberts]

You know, I just remebered that I had a brute-force method of doing the MM spring thing with expressions. It has to loop through the entire time line on every frame so it will undoubtedly bog down in long comps, but here it is:

restLength = 20; //rest length (pixels)
damp = .95;
leader = thisComp.layer(“leader”);

fDur = thisComp.frameDuration;
currFrame = Math.round(time/fDur);

p2 = position.valueAtTime(0);
v2 = 0;
for (f = 0; f <= currFrame; f++){ t = f*fDur; p1 = leader.position.valueAtTime(t); delta = p2 - p1; nDelta = normalize(delta); a = 2*nDelta*(length(delta) - restLength)*fDur; v2 = (v2 - a)*damp; p2 += v2; } p2 Dan