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Tell if a value is positive or negative without IF statement.
I’m trying to determine if my value is positive or negative. Of course I could easily do an IF ELSE statement, but I need this expression to work on 400 layers simultaneously and IF ELSE has proven to slow things down immensely, so I try to find a way without using it.
In an ideal world I would get 1 if my value is positive and -1 if it’s negative, but of course anything else like 1 and 0 or something like this would be great too.
I wrote this tiny expression, which works exactly like I want it to, but fails if the value is 0. Do anybody here know a better way?PosNeg = Math.abs(value)/value; -
4 Replies
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PosNeg = normalize(value);wouldn’t give an error with 0, but would return NaN (‘not a number’).
maybe try and catch….
try {
PosNeg = Math.abs(value)/value;
} catch (err) {
0;
}Kevin Camp
Art Director
KCPQ, KZJO & KRCW -
value >= 0
should give you 0 if negative, 1 if positive (or zero)
Dan
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Perfect! Didn’t know try and catch before. I guess I should read into it. Thank you a lot Kevin.
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Sorry Dan, I don’t get it. I only see how I could determine if a number is positive or negative using this code in an IF statement, but I didn’t want to use an IF statement.
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