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Shape Trim Path matching Line Rotation?
How would I get the 0-360° rotation of a line to match the 0-100% trim path operation on a circle shape?
So that the edge of the circle always lines up with the tip of the line.
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3 Replies
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It should just be some form of this:
tp = thisComp.layer(“Shape Layer 1”).content(“Ellipse 1”).content(“Trim Paths 1”).end;
linear(tp,0,100,0,360)Depending on how you have it set up might need to add the result to (or subtract it from) some offset angle.
Dan
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I see… so it’s like a range mapper! Cool.
If I needed to reverse the process (I forgot I had the rotation already pickwhipped to a null), would it look like:
tp = *pickwhip rotation*
linear(tp,0,360,0,100) -
That sounds right (again, depending on how you have it set up).
Dan
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