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  • Round corner on shape layer

  • Michelle Barralet

    December 13, 2022 at 7:16 pm

    Hi all

    I’m creating a shape layer that extends as you type. There is an expression on the position and size currently to create this, so the shape layer needs to remain as a Path and not converted to a bezier path. In the drop down there are animatable parameters for roundness. I just want to round one corner of my shape layer. Is there an expression that will do this? I’ve attached grabs of the current set up and the single corner I want to curve. Any help would be greatly appreciated, I’m on day 2 of googling and can’t find exactly what I need!

  • Tomas Bumbulevičius

    December 21, 2022 at 3:15 pm

    Michelle, the best way to make this work is to have a separate shape, smaller than your existing one, matched ideally with existing shape’s corner (just with roundness). There is no way to make one-only round corner with native roundness keeping the shape as rect, as far as I known. You could also create a new shape, and mask it out except the corner

  • Dan Ebberts

    December 21, 2022 at 6:22 pm

    I think if you convert the rectangle to bezier and use this path expression, you won’t need the position or size expressions:

    radius = 20;
    p = content("Rectangle 1").transform.position;
    L = thisComp.layer("more info");
    r = L.sourceRectAtTime(time,false);
    ul = fromComp(L.toComp([r.left,r.top]))-p;
    ur = fromComp(L.toComp([r.left+r.width,r.top]))-p;
    lr = fromComp(L.toComp([r.left+r.width,r.top+r.height]))-p;
    ll = fromComp(L.toComp([r.left,r.top+r.height]))-p;
    ur1 = [ur[0]-radius,ur[1]];
    ur2 = [ur[0],ur[1]+radius];
    t = radius*0.5525;
    it = [[0,0],[-t,0],[0,-t],[0,0],[0,0]];
    ot = [[0,0],[t,0],[0,t],[0,0],[0,0]];
    createPath([ul,ur1,ur2,lr,ll],it,ot,true)
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