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Random linking Wind Values
Hey,
Im using particular and think an expression would massively help me out. I am basically looking at randomising the wind values x,y,z but so only one is on at a time. For example if the x value is 1000 then y and z would be 0. If y was 1000 then x and z would be 0 etc etc. What I am looking for is to randomise which wind has a value of 1000 over time basically pushing my particles into a 3D grid like format.
Thanks in advance.
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4 Replies
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I think I’d put the randomizing function in a slider somewhere and have it generate the random integers 0,1, or 2 and have an expression in each of the wind controls watching for its number to pop up in the slider (0 for x, 1 for y, 2 for z). The details depend on how you want the timing to work.
Dan
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Thats kind of the way I was thinking. Im not too hot on expressions so unsure how to say if slider value ‘1’ x value 1000 etc. Not too worried about the randomness as I might key frame the slider.
Could someone start me off.
Thanks
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Like this:
s = effect(“Slider Control”)(“Slider”);
if (Math.round(s) == 1) 1000 else 0Dan
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Thanks for that Dan. Unfortunately I didn’t see it in time but managed to come up with a solution. This works perfectly if anyone if anyone else is interested.
Code on Slider:
holdTime = 0.5; //time to hold each position (seconds)
seed = Math.floor(time/holdTime);
seedRandom(seed,true);
x = random(1,5)
Math.round(x);Code for Wind X Value:
// Make x equal to slider value
x = (thisComp.layer(“Null 2”).effect(“Slider 1”)(“Slider”) )// Set position when x = 1
if (x < 2) thisComp.layer(“Null 2”).effect(“Slider 2”)(“Slider”)// Set position when x = 2
if (x > 1) if (x < 3) thisComp.layer(“Null 2”).effect(“Slider 3”)(“Slider”)// Set position when x = 3
if (x > 2) if (x < 4) 0// Set position when x = 4
if (x > 3) if (x < 5) 0// Set positionwhen x = 5
if (x > 4) 0
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