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Random Hexadecimal digits
I have this expression that will display random hex letters if put into a text layer’s Source Text parameter:
rate = 5;
seed = Math.floor(time*rate);
seedRandom(seed,true);
String.fromCharCode(65 + Math.floor(random(6)));
If I lower the starting CharCode from 65 to 48 to include numbers, I get unwanted punctuation symbols from 58~64.How can I generate purely hex digits?
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3 Replies
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Try changing the last line to this:
Math.floor(random(16)).toString(16).toUpperCase();
Dan
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Brilliant as always!
Can you explain a little bit how that works? Are the symbols being ignored because of the .toUpperCase command? The (16) doesn’t seem to correspond to where the letters are in ASCII table.
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Using 16 as an argument for toString() causes the random integer (0 to 15) to be converted to a hexidecimal (base 16) representation of the number. If you leave off the toUpperCase(), “A” thru “F” will be “a” thru “f”. The ASCII table doesn’t really enter into it.
Dan
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