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IP4 number generator
I’ve got this expression running, but I need leading zeros if any of the values fall beneath 100. Any suggestions?
a = random(198,255).toFixed(0);
b = random(000,255).toFixed(0);
c = random(000,255).toFixed(0);
d = random(000,255).toFixed(0);
a + " :" + b + ":" + c + ":" + d; -
4 Replies
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One way:
a = random(198,255).toFixed(0);
b = random(000,255).toFixed(0);
c = random(000,255).toFixed(0);
d = random(000,255).toFixed(0);
while (a.length < 3) a = “0” + a;
while (b.length < 3) b = “0” + b;
while (c.length < 3) c = “0” + c;
while (d.length < 3) d = “0” + d;
a + ” :” + b + “:” + c + “:” + d;Dan
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Perfect! Thank you!!
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How something more complicated like IPv6? (8 groups of 4 hexidecimal numbers each separated by colons)
such as: 2001:0DB8:02A2:B3FF:FE1E:FF00:0042:8329
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Like this maybe:
s = "";
seedRandom(index,true);
for (i = 0; i < 8; i++){
s += (i == 0) ? "" : ":";
for (j = 0; j <= 3; j++){
s += Math.floor(random(16)).toString(16).toUpperCase();
}
}
Dan
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