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Creating a path or shape layer expression for mathematical function
Hello,
I need to find a way to draw this (image attached) asymptote as accurately as possible, preferably in a shape layer.
Not really the expression type, pretty basic. This was my first attempt:
In Path of Shape Layers:
t=value[1];
n=value[14];
x= Math.cos(n*t)/t+t;
y=Math.sin(n*t)/t+t;
[x,y]I will continue trying to figure out a solution in the meantime, but if someone can easily show me how this can be done directly in a shape layer, I’ll owe you one.
Thanks
t=value[1];
n=value[14];
x= Math.cos(n*t)/t+t;
y=Math.sin(n*t)/t+t;
[x,y] -
2 Replies
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I would do it like this:
1) Make a Null
2) Add this expression to its Position property:
t=time/10;
n=14;
x=100*((Math.cos(n*t)/t)+t);
y=100*((Math.sin(n*t)/t)+t);
[x,y]
3) Convert expression to keyframes:
4) Create a new shape layer with empty path and copypaste Null’s Position keyframes to that Path:
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Brilliant!
Exactly what I needed.
Thank you.
Josh Lindo
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