Creating a path or shape layer expression for mathematical function

[Josh Lindo]

Hello,

I need to find a way to draw this (image attached) asymptote as accurately as possible, preferably in a shape layer.

Not really the expression type, pretty basic. This was my first attempt:

In Path of Shape Layers:
t=value[1];
n=value[14];
x= Math.cos(n*t)/t+t;
y=Math.sin(n*t)/t+t;
[x,y]

I will continue trying to figure out a solution in the meantime, but if someone can easily show me how this can be done directly in a shape layer, I’ll owe you one.

Thanks

t=value[1];
n=value[14];
x= Math.cos(n*t)/t+t;
y=Math.sin(n*t)/t+t;
[x,y]

[Oleg Pirogov]

I would do it like this:

1) Make a Null
2) Add this expression to its Position property:

t=time/10;
n=14;
x=100*((Math.cos(n*t)/t)+t);
y=100*((Math.sin(n*t)/t)+t);
[x,y]

3) Convert expression to keyframes:

4) Create a new shape layer with empty path and copypaste Null’s Position keyframes to that Path:

[Josh Lindo]

Brilliant!

Exactly what I needed.

Thank you.

Josh Lindo