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counter expression
Hi. I have a value that is rounded to 0 and 1, coresponding to the beats of a song.
I would like to count each time the value touch 1. i guess it should be a loop expression that ends with a i++ if (n==1).
Any help is more than welcomed.
Thank you
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2 Replies
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This should work, but there might be a more efficient way to do it, depending on what’s driving your value (for this example, I’m assuming the value is contained in a slider):
s = effect("Slider Control")("Slider");
f = timeToFrames(time);
above = s.valueAtTime(0) >= 1;
n = above ? 1 : 0;
for (i = 1; i <= f; i++){
if (above){
if (s.valueAtTime(framesToTime(i)) < 1){
above = false;
}
}else{
if (s.valueAtTime(framesToTime(i)) >= 1){
n++;
above = true;
}
}
}
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An efficient workflow will be to leave the Expression as is and then use a script to do the counting. Again, this may be more efficient OR NOT depending on your workflow.
My thoughts are to let Expressions do quick calculations and then use scripts to perform one-off calculations – as a rule of thumb.
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