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Converting one layer’s rotation to another’s Y value
I’m trying to use a range mapper to convert Layer A’s Z Rotation (0-45°) to Layer B’s Y Position (+/- 100 pixels). Both are 3D layers.
I think I have the basic concept correct? But I’m getting a class number error in last line of this:
input = thisComp.layer("Layer A").transform.zRotation;
inputLow = 0;
inputHigh = 45;
outputLow = -100;
outputHigh = 100;
m = linear(input,inputLow,inputHigh,outputLow,outputHigh);
[value[0], value + m[1], value[2]] -
5 Replies
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I haven’t tried it, but I think you just need to change the last line to this:
[value[0], value + m, value[2]]
or this,
value + [0,m,0]
Dan
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Your solution works great (of course)!
Generally speaking, when should I be use (and not use) [0], [1], [2]? I thought 3D position was an array.
Also, should I be using degreesToRadians?
In the meantime, I came up with this. But it feels clunky:
x = thisComp.layer("green").transform.position[0];
y = thisComp.layer("green").transform.position[1];
z = thisComp.layer("green").transform.position[2];input = thisComp.layer("solid").transform.rotation;
inputLow = -45;
inputHigh = 45;
outputLow = -100;
outputHigh = 100;
m = linear(input,inputLow,inputHigh,outputLow,outputHigh);
[x, y+m, z] -
I may have added to your confusion. I got the first option wrong. It should have been:
[value[0], value[1] + m, value[2]]
> I thought 3D position was an array.
It is. But your variable m isn’t, so it doesn’t need array indexing. I like the second option (value + [0,m,0]) where you just let AE do the vector (array) math for you.
>Also, should I be using degreesToRadians?
Generally not unless you use one of the JavaScript trig functions.
Dan
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[value[0], value[1] + m, value[2]]
value + [0,m,0]
They both work fine. Is there a reason I should use one over the other?
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Functionally they’re the same. I like the second one because it’s more efficient (and tidier code, I think). The expression engine knows how to add arrays, so I say take advantage of it. 🙂
Dan
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