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Any way I can make this recursive expression elegant?
Basically, I like the result of the ‘easeOut’ expression, but wanted it a little ‘sharper’. Unfortunately, the only way I could seem to get it some what desirable was repeat the expression over and over again so the the ease was stronger. I know there has GOT to be a better way, if anyone could point me in the right direction for my future expression I’d appreciate it.
Thank you.
G1 = transform.position+[0,100];
G2 = transform.position;
finalPoint = inPoint+[1];
f = easeOut(time,inPoint,finalPoint,G1,G2);
f;
l = easeOut(time,inPoint,finalPoint,G1,f);
l;
j = easeOut(time,inPoint,finalPoint,G1,l);
j;
easeOut(time,inPoint,finalPoint,G1,j); -
1 Reply
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I don’t know that this is much better:
G1 = transform.position+[0,100];
G2 = transform.position;
finalPoint = inPoint+[1];
easeOut(easeOut(easeOut(easeOut(time,inPoint,finalPoint,0,1),0,1),0,1),G1,G2)You probably could set it up as a recursive call, but I instead of doing that I would go to Penner’s quartic ease out formula.
Dan
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