• Adobe After Effects Expressions

  Problem with the order of actions. how to create a slider without losing the original property selection array

  Posted by Tal Arbiv on December 12, 2016 at 12:33 am

  I’ve got a double ‘for’ loop creating expressions on a selected properties of selected layers. the expression contains reference to a slider that is created on current layer within the same loop.
  problem is, if i place the slider creation after the expression assignment, the non existing reference breaks the loop,
  and if i place it after, my guess is that it replaces the active selection of the original property with the newly created slider and that messes up the rest of the loop .

  result 1 : faulty expression
  result 2 : expression assignment skipped

  // (1) :

  expr = “effect(‘name’)(‘slider’) //+something+something…. ;
  for (i=0; i <= sellayers.length-1; i++){
  for (p=0; p <= selprop.length-1; p++){
  selprop[p].expression = expr;
  }
  ofset = sellayers[i].Effects.addProperty(“ADBE Slider Control”);
  ofset.name = “name”;
  ofset.property(“Slider”).setValue(0);
  }
  // (2) :

  expr = “effect(‘name’)(‘slider’) //+something+something…. ;
  for (i=0; i <= sellayers.length-1; i++){

  ofset = sellayers[i].Effects.addProperty(“ADBE Slider Control”);
  ofset.name = “name”;
  ofset.property(“Slider”).setValue(0);

  for (p=0; p <= selprop.length-1; p++){
  selprop[p].expression = expr;
  }
  }

  Big thank you in advance

  // (1) :

  expr = "effect('name')('slider') //+something+something.... ;
  for (i=0; i &lt;= sellayers.length-1; i++){
  for (p=0; p &lt;= selprop.length-1; p++){
  selprop[p].expression = expr;
  }
  ofset = sellayers[i].Effects.addProperty("ADBE Slider Control");
  ofset.name = "name";
  ofset.property("Slider").setValue(0);
  }
  // (2) :

  expr = "effect('name')('slider') //+something+something.... ;
  for (i=0; i &lt;= sellayers.length-1; i++){

  ofset = sellayers[i].Effects.addProperty("ADBE Slider Control");
  ofset.name = "name";
  ofset.property("Slider").setValue(0);

  for (p=0; p <= selprop.length-1; p++){
selprop[p].expression = expr;
}
}


  Tal Arbiv replied 9 years, 8 months ago 1 Member · 0 Replies
• 0 Replies

Reply to this Discussion! Login or Sign Up