[Steve Sierra]

Hi,

I think this works (t is the Y animation duration in seconds):

X=position[0];
Y=position[1];
a = thisComp.height;
t = 4;

[X,linear(t, -a/2, (1.5*a*time/t)-((a/(2*t))*(t-time)))];

if(time>=t){
[X, -a/2]
};

Here’s what I think is going on :
I first wanted to put a linear interpolation and then check the time to send it back to it’s original position.
Since the final value is in an if statement, it recalculates the value every frame, so a simple linear doesn’t work.
I then noticed that it was tacking the last value of the linear interpolation in account.
So I modified that final destination value to “fit” the animation…

Hope this helps !
😉

[Steve Sierra]

Hi,

You can transition from shape to shape directly in one shape path.
You create a path for every shape in your animation, create a key, and copy/past it to your main shape path at the right time. This way, your main shape path is keyframed and your blue layer will follow.

If the interpolations between the shapes don’t please you, you can copy/past all your main shape path keys to a mask path, use the mask interpolation tool (Window/Mask Interpolation), then copy/paste the newly generated keys back to the main shape path.

I would also directly reference the main shape layer by name in your blue position expression… That way, you can add layers without having problems :

delay = 1
d = delay*thisComp.frameDuration*(index – 1);
thisComp.layer(“Line”).position.valueAtTime(time – d)

I hope this helps !
Good luck 😉

[Steve Sierra]

Hi,

I think you should check this out :

https://www.motionscript.com/design-guide/marker-sync.html

😉

[Steve Sierra]

Hi,

I haven’t tested it, but I think this should work too:

StatsCats = thisComp.layer(“Number of Stats Categories”).text.sourceText;
NumCol = thisComp.layer(“Number of Columns”).text.sourceText;

if(StatCats == 1 || StatCats == 3){
c = 855;
}else{
c= 860;
};

[1950 – (NumCol * 250), c – (StatsCats * 60)];

Dan’s solution is way more flexible, though !
Cheers !;)

[Steve Sierra]

Hi again,

Try putting your clamp in your n variable…

n = clamp(thisComp.layer(“CONTROLS”).effect(“Focus on layer”)(“Slider”), 5, thisComp.numLayers);
Z = thisComp.layer(n).transform.position[2];

Z-(thisComp.layer(“Cam control”).transform.position[2])

Cheers !

[Steve Sierra]

Hi,

You can’t have n = 0, since it is used as the layer index in Z (indexes start at 1).
What happens when your (“Focus on Layer”) slider hits 0 ?

I think you should do an if/else statement to set a default value to your focal distance when the slider is at 0.

Hope this helps ????

Cheers !

[Steve Sierra]

Hi everyone,

I am reviving this thread because I am having the same problem with my script…

I think what is going on is that every time a value linked to one of the checkboxes is changed, all the checkboxes momentarely use their pre expression value (which is the last state it was in) and therefore ultimately go back to a “default state”.
(I think this is going on because when I change the value of a slider linked to one of the checkboxes with the mouse and don’t let go of the left click, I can see the other checkboxes last states. When I let go of the left mouse button, the checkboxes have changed.)

Is it possible to prevent this ?

Thanks 😉

[Steve Sierra]

Very nice !!
I didn’t know about the “continue”…
I see it stops the text layer from seeing the disabled layers.
Could you please explain how it works ?

Many thanks 😉

[Steve Sierra]

That’s exactly it !

The “break” stops the for loop if a layer is found underneath the text layer.

The second expression also :
– checks if the outPoint is after time, so it stops displaying the name once the layer is cut.
– the else part makes the text layer display nothing (“”) if there is no layer underneath.

Cheers !
😉

[Steve Sierra]

This is even better :

a = thisLayer.index;
b = thisComp.numLayers;
for(i = a+1; i <= b; i++){
curLay = thisComp.layer(i);
if(curLay.inPoint < time && curLay.outPoint > time){
curLay.name;
break;
}else{
“”
}
}

😉