[Scott Mcgee]

Not quite sure if you need such a complex expression. Something as simple as this would work on the opacity.

time < inPoint;
ease(time-inPoint,0,1,0,100)

If you are wanting to change the value with ease without constantly having to go into the expression and change the start time or move the layers inPoint. I use a text layer because I need to change the value all the time and have this set up.

s = parseInt(thisComp.layer(“Amount”).text.sourceText);
if (isNaN(s)) s = 0;
t = s + 1;
ease(time,s,t,0,100)

Hope this is of help.

[Scott Mcgee]

Genius,

I replaced \r with another symbol that will never be used so I can use [0],[1],[2] and so forth.

Cheers for the help.

[Scott Mcgee]

Hey Dan,

That’s just what I wanted, so I don’t have to worry about Excel exporting it with “”

So now I have one last question. I’ve not done anything like this before so I haven’t the foggiest (I’ve tried something you put in another forum), I’m hoping you might have a solution.

It now appears

“””
“RSS FEED”\r”
“RSS FEED”\r”
“RSS FEED”\r”
“””

Is there an expression to only read a single line?

I have 3 text layers. In the feeds they contradict one another, which is why I would prefer not to do it this way, but I have to make the best of a crappy situation.

I’ve included \r to paragraph it, but I don’t know how to get Text 1 to look at line 1, Text 2 to look at Line 2 and Text 3 to look at Line 3.

I can’t substr it, as the character length will differ everyday so it needs to look at the line. I saw you gave an expression to “lineIdx”, I’ve tried playing around with it, with no success.

[Scott Mcgee]

Cheers Dan,

Understandable.

Ok, another route we could do, is have the machine convert the data to .txt

But excel is exporting it like this.

“Text1 = “RSS FEED”;”
“Text2 = “RSS FEED”;”

If I go in and manually delete the “” at the front and end of each line, this works fine. Otherwise it won’t work.

Is there a way to convert this expression to look between “” on each line?

$.evalFile(“filepath”);
eval(“Text1”);

[Scott Mcgee]

Found it

input = thisComp.layer(“station”).text.sourceText;

if (input.indexOf(“Bristol”) != -1) {
100
} else {
0
}

Just incase anyone else has this issue

[Scott Mcgee]

Color Control is what you need.

Create a null object, call it “Color Controller”, or whatever you want to call it. Add your color control which is in the effects > expression controls.

All you need to do is apply a fill to all items you want to be that specific color and pick whip them to the color controller.

When you change the color then on your color controller, it will change all the items linked to it, with the same color.

[Scott Mcgee]

Hey Tobias,

Not sure what you are trying to do.

The expression is fine, if you are wanting to change the input of Keyframe 2 with a value defined by your slider.

but it doesnt work because the slider control itself has no changing value

How do you want the value to change? Based off what you described firstly, your expression is fine.

[Scott Mcgee]

I just about understand.

when i googled and read the first line on the first page I opened

A regular expression, regex or regexp[1] (sometimes called a rational expression)[2][3] is, in theoretical computer science and formal language theory,

First thing I thought…I hate my life right now.

But watched 1 youtube video, it seems straight forward.

Thank you for explaining.

[Scott Mcgee]

Genius Dan,

Just because this is the first time, yourself or anyone have given me an expression that I couldn’t work out myself when reading it.

Could you break this down please. As I haven’t the foggiest what any of the line 1 means passed r =. line 2 I get the gist and line 3 is a bit of a mystery aswell passed txt.replace.

[Scott Mcgee]

Got the answer (ish), need too fine tune, but it does what I need.

//BTN: to apply selected listbox item
var myBtn = w.add (“button”, undefined, “Apply”);

myBtn.onClick = function(){

var listSel = myList.selection;
var myComp = app.project.activeItem; if(!myComp || myComp.typeName !== “Composition”) return;
var n;

for (n=0; n