[Dan Ebberts]

Interesting idea. This seems to work. You need to convert the VO track to keyframes. Fiddle with the four parameters until you get something you like. The squelch parameter assumes your bed is stereo – just change it to a single number if it’s mono.

silenceLevel = 5; // volume level of VO where squelch is removed
silenceTime = 1.0; // length of silence before bed starts to ramp up
rampTime = 0.5; // time to ramp up bed
squelch = [12, 12]; //amount to squelch bed (db)

VO = thisComp.layer(“Audio Amplitude”).effect(“Both Channels”)(“Slider”); //VO level

if (silenceLevel > VO.value){
t = time;
while (t > 0 && t > time – (silenceTime + rampTime)){
t -= thisComp.frameDuration;
if (VO.valueAtTime(t) >silenceLevel) break;
}
if (time – t > silenceTime){
linear(time – t, silenceTime, silenceTime + rampTime, value – squelch, value);
}else{
value – squelch;
}
}else{
value – squelch;
}

Dan

[Dan Ebberts]

Do you have 3D layers occupying the same space? For example, if your dark brown stuff is at the same z depth as the light brown, the it can ambiguous as to which layer is closer to the camera. In that case you’d just need to move the light brown a small distance away.

Dan

[Dan Ebberts]

I don’t think that’s really what you want. If you really used a value of infinity there, you wouldn’t see any decrease in value as you moved away from the camera.

What you’re probably really after is an exponential decrease based on the distance from the camera.

Dan

[Dan Ebberts]

Give this a try (for position):

chkBx = effect(“Checkbox Control”)(“Checkbox”);

n = 0;
if (chkBx.numKeys > 0){
n = chkBx.nearestKey(time).index;
if (chkBx.key(n).time > time){
n–;
}
}

t = 0;
curTime = time;

if (n > 0){
for (i = n; i > 0; i–){
if (chkBx.key(i).value > 0){
t += (curTime – chkBx.key(i).time);
}
curTime = chkBx.key(i).time;
}
if ((curTime > 0) && (chkBx.key(1).value > 0)) t += curTime;
}else{
if (chkBx.value > 0) t = time;
}

sp=2;
amp=150;
gravity = 50;
x = Math.sin(t*sp)*amp;
y = Math.sin(t*1.5)*50;
value + [x,y];

Dan

[Dan Ebberts]

What’s the code for your expression?

Dan

[Dan Ebberts]

An interesting little trig problem. I’ll give it some thought if nobody else chimes in.

Dan

[Dan Ebberts]

You mean the x axis? I think it would be like this:

factor = .5;
delta = toWorld(anchorPoint) – thisComp.activeCamera.toWorld([0,0,0]);
radiansToDegrees(Math.atan2(-delta[1],delta[2]))*factor + value*(factor – 1)

I’m not sure how they’ll interact if you use x and y at the same time though.

Dan

[Dan Ebberts]

Something like this might do it:

factor = 25;
minX = 0;
maxX = 2000;
minY= 480;
maxY = 520;
minZ= 0;
maxZ = 500;
temp = gaussRandom([minX,minY,minZ],[maxX,maxY,maxZ])
x = Math.round(temp[0]/factor)*factor;
y = Math.round(temp[1]/factor)*factor;
z = Math.round(temp[2]/factor)*factor;
[x,y,z]

Dan

[Dan Ebberts]

>I’m curious to see if this matches my internal hype — or not.

Me too. 🙂

Dan

[Dan Ebberts]

This should do it:

factor = .5;
delta = toWorld(anchorPoint) – thisComp.activeCamera.toWorld([0,0,0]);
radiansToDegrees(Math.atan2(delta[0],delta[2]))*factor + value*(factor – 1)

Adjust factor between 0 and 1 to get less or more follow.

Dan