[Dan Ebberts]

Without seeing what you’ve done, my guess would be that it’s a pixel aspect ratio thing (square pixel layers in a rectangular pixel comp?) If so, you’ll save yourself a lot of aggravation by working in a square pixel comp and fitting it inside your rectangular-pixel output comp when you’re done.

Dan

[Dan Ebberts]

This time-remapping expression should do it:

f = thisComp.frameDuration;
frames = Math.round(time/f);
(Math.floor(frames/2)*3 + frames%2)*f

Dan

[Dan Ebberts]

This time-remapping expression should do it:

f = thisComp.frameDuration;
frames = Math.round(time/f);
(Math.floor(frames/2)*3 + frames%2)*f

Dan

[Dan Ebberts]

Try this:

linear(time,0,4,100,150)

If you only want integers, it would be like this:

Math.round(linear(time,0,4,100,150))

Dan

[Dan Ebberts]

Try this:

linear(time,0,4,100,150)

If you only want integers, it would be like this:

Math.round(linear(time,0,4,100,150))

Dan

[Dan Ebberts]

I’d split the layer at the switch point and re-parent the second piece.

Dan

[Dan Ebberts]

If you want the follower layers to have the same orientation as the leader layer, but time delayed, apply this expression the their rotation property (leave auto-orientation off for the followers):

delay = 0.25;
t = time – delay;
L = this_comp.layer(“leader”);
x = L.toWorldVec([1,0],t);
radiansToDegrees(Math.atan2(x[1],x[0]));

Dan

[Dan Ebberts]

If you want the follower layers to have the same orientation as the leader layer, but time delayed, apply this expression the their rotation property (leave auto-orientation off for the followers):

delay = 0.25;
t = time – delay;
L = this_comp.layer(“leader”);
x = L.toWorldVec([1,0],t);
radiansToDegrees(Math.atan2(x[1],x[0]));

Dan

[Dan Ebberts]

If you just want to subtract 1 from the layer’s z value you could do it like this:

thisComp.layer(“Layer 1”).position – [0,0,1]

The easiest way to express a value as the three individual coordinates would be to do something like this:

p = thisComp.layer(“Layer 1”).position;
[p[0],p[1],p[2]]

It’s all just JavaScript array notation.

Dan

[Dan Ebberts]

If you just want to subtract 1 from the layer’s z value you could do it like this:

thisComp.layer(“Layer 1”).position – [0,0,1]

The easiest way to express a value as the three individual coordinates would be to do something like this:

p = thisComp.layer(“Layer 1”).position;
[p[0],p[1],p[2]]

It’s all just JavaScript array notation.

Dan