Forum Replies Created

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  • Barry Suydam

    April 15, 2011 at 7:04 pm in reply to: decaying bounce off imaginary wall

    I have a text layer that after a time passes in the comp I want it to start a decaying swing and land perpendicular to its start point. Any help would be great.

  • Barry Suydam

    April 15, 2011 at 6:06 pm in reply to: decaying bounce off imaginary wall

    Thanks again….you are great!

  • Barry Suydam

    March 18, 2011 at 3:15 pm in reply to: Computer type write effect

    n=8;
    showtext=text.sourceText.substr(0,n)+”_”;

    I used this code and it on accident gave me exactly what i needed. Thanks. What I was looking for was to have text type on inversely to normal. Usually you type in a linear fashion…what I was looking for was for each letter to push the previous letters index away from the words anchor point. so if a word is right justified it types out to the left but from its right justified anchor point. Confused yet? Sorry

    Your code did this perfectly, however when doing the exact opposite the text types on like usual.(Left justified typed out one letter after the other…unwanted) Any way to duplicate the wanted behavior would be much appreciated.

  • Barry Suydam

    March 18, 2011 at 1:35 pm in reply to: Opacity Driven Expression

    Great, thanks…

    I found this expression on your website////

    point1=this_layer.position;
    point2=thisComp.layer(“Text Bar”).transform.scale;

    delta=sub(point1, point2);

    distance=length(delta);
    linear(distance, 0,50, [150,150],[100,100]);

    What I am trying to accomplish is as that bar moves past the text layer it moves the layer position 50 pixels on the x axis only and once it passes completely it returns to its original value. So what I came up with is the following however it don’t work. Any help would be appreciated.

    point1=this_layer.position;
    point2=thisComp.layer(“Text Bar”).transform.position;
    x = value =50
    delta=sub(point1, point2);
    distance=length(delta);
    ease(distance, 0,50, [x,[1]],[[0],[1]]);

  • Barry Suydam

    March 16, 2011 at 7:08 pm in reply to: Opacity Driven Expression

    It is an honor to be educated by Mr. Ebberts himself. It worked as it should. Thank you so much. Is there a simple way to ease in the opacity. If so that would be over the top assistance? Thanks again Dan.

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