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decaying bounce off imaginary wall
I have a verticle thin line with its anchor point set at the top of the viewable composition. what I am trying to attain is to have it rotate into its virticle position with a decaying bounce off an imaginary wall. Any help? So far I have this expression applied but it swings through the imaginary wall.
veloc = -50
amplitude = -90
decay = 4;
y = amplitude*Math.cos(veloc*time)/Math.exp(decay*time);
value + y -
6 Replies
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Just change the 4th line to this:
y = -Math.abs(amplitude*Math.cos(veloc*time)/Math.exp(decay*time));
Dan
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Thanks again….you are great!
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I have a text layer that after a time passes in the comp I want it to start a decaying swing and land perpendicular to its start point. Any help would be great.
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Like this, probably:
timeToStart = 3;
veloc = -50
amplitude = -90
decay = 4;
t = Math.max(0,time-timeToStart);
y = -Math.abs(amplitude*Math.cos(veloc*t)/Math.exp(decay*t));
value + yDan
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I thank you again.
The world of after effects expressions is lucky to have a person like you to be able to throw out a problem and have a solution so fast. I am not sure where you live or who you work for but thank you. I have a fair understanding of expressions because of your website and jjgifford.com, much appreciated. Is there another resource like those that I haven’t found. I just wish I could do better and more with applying expressions. I wish I worked with some more folks like you.
-Barry -
Thanks for the kind words Barry, I appreciate it.
>Is there another resource like those that I haven’t found.
I’m afraid I haven’t kept track of what’s out there. I am working on a long-overdue update to my own site that should make it a much better resource.
Dan
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