Z pass using expressions

[Dan Ebberts]

Try this:

start = 0;
vanish = 1000;
linear(position[2],start,vanish,100,0)

Adjust start and vanish to suit.

Dan

[Cory06]

Wow!! You are good. That

[Cory06]

While I have your attention, I was wondering if i could ask one more question. if i want one object A to to derive it’s z position from object B’s z postion, can i do that while leaving Object A’s X&Y independant with an expression??

only if you have time

thanks again

[Dan Ebberts]

Like this:

p = thisComp.layer(“object B”).position;
[value[0],value[1],p[2]]

Dan

[Cory06]

Thanks again!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!