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Vertical distribution depending on which layers are visible.
I’m creating a schedule and have 7 comps, one for each day, distributed vertically. Within each comp is a text layer, if the text layer contains no characters it turns the parent comp opacity to 0.
How can I set those 7 parent comps up so that as their opacities change to 0 the remaining comps reposition to maintain an even distribution?I
‘m assuming some kind of array unique to each layer – if (x) amount of layer opacities set to 0 – set Y position to…?
This is set to be driven by essential graphics so it’s important than any layer can be turned off and the rest react accordingly.
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3 Replies
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This is a simple example with lots of assumptions. It assumes that the layers participating are at the top of the layer stack (layers 1 thru n). It expression counts the number of layers above its host layer that have opacity = 0. For each of those it finds, it move upwards a distance equal to its own height.:
n = 0;
for (i = 1; i < index; i++){
if (thisComp.layer(i).opacity == 0) n++;
}
value - [0,n*height] -
Thanks Dan! That’s definitely in the right direction, it’s doing exactly what I need in terms of repositioning the comps but I need them all to stay centrally aligned in order to wrap the shape layer around them all.
I can do the shape layer via sourceRectAtTime but would the central alignment be via a separate Nul or baked into the position expression?
Images attached for more clarity.
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I think the expression would need to know the gap between layers. Then something like this would work (it assumes all layers in the comp are participating):
gap = 50
n1 = 0;
for (i = 1; i < index; i++){
if (thisComp.layer(i).opacity == 0) n1++;
}
n2 = 0;
for (i = index+1; i <= thisComp.numLayers; i++){
if (thisComp.layer(i).opacity == 0) n2++;
}
value - [0,(n1-n2)*(height +gap)/2]
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