-
use effectors on objects without Clone
assuming I have hundreds of objects, I reduce the matter to 4 cubes..
if I use a random effector as in the example of the image below, if I act for example on the parameters on the Y axis at -320 (with the Max effector at 100% and Min at -100%), the cubes are moved towards the bottom, so the same will be done with respect to the parameters that I will insert in the X and Z axes, in practice you will obtain a movement towards the indicated directions
if I use the same effector on a cube inserted in a Clone the movement I will obtain with the same random effector will be different, it will push the cubes in the opposite direction in the Y axis (the two cubes above upwards and the two below downwards) , but in a non-linear way in the example, despite all having the same value, the cube on the top right went higher than the one on the top left and vice versa those below.
Is there a system or formula that allows objects to do the same thing, starting from precise coordinates and then expanding, but without using Clone, since I already have several hundred objects to move positioned in an environment?
-
4 Replies
-
Hi Sempre,
If I understood your problem well, then making the max and min values equal should make the two cubes move together with the same start and stop coordinates. If you want to make them move in opposite directions but with the same coordinates, you can do that by changing the Random mode to Sorted as in the screen recording below. let me know if this is what you are looking for.
-
No
I attach a c4d file which makes it clear what I wanted, in practice obtaining the same movement with the random effector but applied to the object without therefore using the MoGraph generators
-
I changed the Random Mode to Noise and set some values as in the screen recording so got a very similar effect as in the screen recording but it needs some improvement, I don’t know if this is enough for you or not but I think this is the right start to get a perfect simulation without Mograph.
-
thanks a lot
Reply to this Discussion! Login or Sign Up