Turn off sequentially

[Dan Ebberts]

It will probably be something like this, which should turn the layers off sequentially, starting at 1 second and then every .25 seconds:

tStart = 1;
tDelay = .25;
time >= (tStart + (index-1)*tDelay) ? 0 : value

Dan

[John Madison]

Thanks,

How would i go about reversing it if possible, so that the bottom layer goes off first instead of the top layer?

[Dan Ebberts]

If all layers in the comp are participating, it would be like this:

tStart = 1;
tDelay = .25;
time >= (tStart + (thisComp.numLayers – index)*tDelay) ? 0 : value

Dan

[John Madison]

Thanks Dan!

I thought I had it, but not quite! What I wanted was the layers to turn on sequentially and then off again sequentially.

So in the set-up, I have 20 layers arranged top to bottom. I would like them to turn on one by one and then once all are on, they start to go off again sequentially.

I thought the expressions above would do it with some tweeking but finding it really difficult!

[Dan Ebberts]

Like this maybe:


tStart = 1;
tDelay = .25;
if (time < tStart + thisComp.numLayers*tDelay)
time >= (tStart + (index-1)*tDelay) ? value : 0
else
time >= (tStart + (thisComp.numLayers + index-1)*tDelay) ? 0 : value;


Dan

[John Madison]

Many thanks Dan, but its still not quite what i wanted. I should’ve explained better.

I want them to turn on from bottom up and then turn off immediately after from top down.

[Dan Ebberts]

Try this:


tStart = 1
tDelay = .25;
if (time < tStart + thisComp.numLayers*tDelay)
time >= (tStart + (thisComp.numLayers-index)*tDelay) ? value : 0
else
time >= (tStart + (thisComp.numLayers + index-1)*tDelay) ? 0 : value;


Dan

[John Madison]

perfect!

[Navarro Parker]

How about an expression where all layers start out visible. Then sequentially, each layer blinks off then comes back on before the next one blinks off, then back on.

such as this:

[Dan Ebberts]

Something like this maybe:


tDelay = .3;
tOff = .1;
tOn = .2;

idx = Math.floor((time - tDelay)/(tOff+tOn));
if (idx == (index -1))
if ((time - tDelay)%(tOff+tOn) > tOff) value else 0
else
value


Dan