Shape length

[Dan Ebberts]

If you know the diameter (or can get it sourceRectAtTime()) it’s just

diameter*Math.PI

If it’s a path, you can approximate the length by using pointOnPath() to chop the path into a bunch of tiny pieces and summing their lengths together, like this:

path = content("Circle").content("Path 1").path;
numPts = 100;
accum = 0;
for (i = 0; i <= numPts; i++){
  if (i == 0){
    p1 = path.pointOnPath(0);
  }else{
    p0 = p1;
    p1 = path.pointOnPath(i/numPts);
    accum += length(p0,p1);
  }
}
accum

[Ione Mabe]

Thank you, Dan!!!
Chopping the path is precise enough to do the job!