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Real Quick Expression Question
I’m having trouble with IF statements
What I want is if a checkboxA is off then checkboxB is off but if CheckboxA is on then CheckboxB be can be on or off
I have (not exactly but close enough)
If(thiscomp.layer.effect(“Paint Layer”)=0)thiscomp.layer.effect(“Paint Layer”)
Which should mean if CheckboxA is 0 then this checkbox is 0. I get a ‘can’t appear on the left hand side of an assignment, because it is read only” error
what am I doing wrong
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7 Replies
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This should do it:
if(effect(“Paint Layer”)(“Checkbox”) == 0) 0 else value
Dan
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Hi
why not just pickwhiping CheckboxA with the other Checkbox? -
Because he only wants to force the values to be the same if the first checkbox is off.
Dan
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Well, I found an obvious work around but I still wanted to try to get this to work and it’s still a no go.
This is exactly what I have
if(thisComp.layer(“input Output”).effect(“Paint Layer”)(“Checkbox”)= 0) 0 else value
I have tried a bunch of variations. Generally always got the same error.
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Oh… got it. I thought the == was a typo and when I tried using the double equals I must of already had something else screwing it up.
Can you tell me why it needs two equal signs?
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in Javascript (and many other languages)
= means ‘assign a value’ or ‘set to’ as in: var foo=”hello”;
== means ‘is equal to’ as in: if (foo==”hello”)
when you ask if(foo=”hello”), you’re setting foo, and the if checks the result value of that operation (usually it’s true, because the setting of the variable was succesful);
so not only is this always true, after if(fo=”hello”), you’ve erased the previous value of foo.Makes sense ?
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Yeah, that makes sense.
My programming skills never went much further than Qbasic. (Although I know the hell out of it!)
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