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random numbers in steps of 5
hi,
i´m to bad in afx expressions for this…
i would like to generate random numbers, but in steps of five. like 45-70-15 etc.
would be very nice if someone knows a way to achieve this!
thankyou, regards
andi -
2 Replies
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value = Math.floor((random()*20))*5
generates numbers divisible by 5, and a maximum of 100.
(in fact it generates random numbers from 0 to 20 (the first value in bold) multiplied by 5 (the 2nd value in bold) -
thank you so much!
always a pleasure someone taking his valueable time 🙂
best wishes!
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