Random Movement Expression

[Dan Ebberts]

Ah, the old random motion on a grid expression. So you want the objects to start out as an array that form a picture and at some point break into random grid motion, is that correct? If so, do the pieces fill the grid or is the grid bigger? If the grid is bigger, are the pieces arranged at the center? Or is it something else entirely?

Dan

[Curses]

Well, i either want it to form the final object, or start with the final object and break apart, from there i can either reverse the time or do anything i want with it, just at 1 point it needs to be on the final object.

[Dan Ebberts]

If you make a small change to the expression, the pieces will start from wherever you place them:

origin = [10,10]; //upper left hand corner of grid
dimX = 8; //number of columns
dimY = 6; //number of rows
gap = 20; // distance between cells (pixels)
gridRate = 300; //speed (pixels per second)
holdTime = .2; //(seconds)

end = 0;
j = 0;

while (time >= end){
  seedRandom(j,true);
  
  startX = Math.floor(random(dimX))*gap + origin[0];
  startY = Math.floor(random(dimY))*gap + origin[1];
  if (j == 0){
    startX = value[0];
    startY = value[1];
  }
  j +=1;
  seedRandom(j,true)
  start = end;
  endX = Math.floor(random(dimX))*gap + origin[0];
  endY = Math.floor(random(dimY))*gap + origin[1];
  deltaX = Math.abs(endX - startX);
  deltaY = Math.abs(endY - startY);

  end += (deltaX + deltaY)/gridRate + 2*holdTime;
}

p1 = start + deltaX/gridRate;
p2 = p1 + holdTime;
p3 = p2 + deltaY/gridRate;

if (time < p1){
  ease(time,start,p1,[startX,startY],[endX,startY])
}else if (time < p2){
  [endX,startY]
}else if (time < p3){
  ease(time,p2,p3,[endX,startY],[endX,endY])
}else{
  [endX,endY]
}

Dan