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Ping Pong Loop of Color Fill
Hi,
I would like to loop the fill color of a layer, so it fades from blue to gray, gray back to blue and repeats forever.
I have two ideas but they don’t seem to be working. Is there a simple way to ping pong loop “linear”? (I tried a little If statement that played a reverse version of the linear, but it introduced a color flash)
Maybe there is a better way with a Sin curve driving the transition?
Bonus if there is variable to hold at the point it is full gray and full blue.
Thank you in advance!
Paulblue = thisComp.layer("COLORS").effect("Color1")("Color")
gray = thisComp.layer("COLORS").effect("Gray")("Color")
loopTime = 1;
t = time % loopTime;
linear(t, 0, loopTime, blue, gray) -
3 Replies
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Try this:
blue = thisComp.layer(“COLORS”).effect(“Color1”)(“Color”);
gray = thisComp.layer(“COLORS”).effect(“Gray”)(“Color”);
loopTime = 1.;
holdTime = .5;
t = time % loopTime;
loops = Math.floor(time/loopTime);
if (loops%2)
linear(t, 0, loopTime-holdTime, gray, blue)
else
linear(t, 0, loopTime-holdTime, blue, gray);Dan
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Hi,
Thank you Dan.
If you have time, would you mind breaking it down, in particular how the if with the modulus works…
if (loops%2)
Thanks,
Paul -
loops%2 evaluates to true if there have been an odd number of loops (not counting the current one).
Dan
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