Peak value calculation

[Andrei Popa]

This should work.
a =thisComp.layer("Shape Layer 1").transform.yPosition
max = 0;
for(i = 1;i<=a.numKeys;i++){
if (a.key(i).time <= time) max = Math.max(max, a.key(i).value);
}
max

Andrei
My Envato portfolio.

[Dan Ebberts]

I’d try it this way:


a = thisComp.layer("Layer1").transform.yPosition;
max = a.value;
for (i = 1; i <= a.numKeys; i++){
if (time < a.key(i).time) break;
max = Math.max(max,a.key(i).value);
}
max


Dan

[Vince Babbra]

This works perfect guys… thank you so much… One final question, if I wanted the inverse, I wanted it to output the MINIMUM value instead, what would I need to change!?

Thx so much!

[Andrei Popa]

You should use Math.min instead of Math.max

Andrei
My Envato portfolio.

[Vince Babbra]

Hmm, using Math.min instead of Math.max does not work? It just returns a single value…

[Andrei Popa]

Maybe the first value is tha absolute minimum… I have just tried it and it work on my side.

Andrei
My Envato portfolio.

[Vince Babbra]

This is very strange. Please see here, what am I doing wrong?

https://www.dropbox.com/s/xcso312gkk2i6o0/Math%20Min%20Problem.mp4?dl=0

Thanks in advance!

[Andrei Popa]

You will have to excuse my delay, i had to go to sleep and just got to the office right now. I have tested it with Dan’s expression and worked. The difference is that in my expression, i initiate the min with 0, which stays the minimum for all the duration. That is why it didn’t work. The big difference between Dan’s expression and mine is that his shows the value as it changes, while mine just snaps when getting to the keyframe. I recommend you try both. So for mine to work just change min initialization and use Math.mina =thisComp.layer("Shape Layer 1").transform.opacity
max = a.key(1).value;
for(i = 1;i<=a.numKeys;i++){
if (a.key(i).time <= time) max = Math.max(max, a.key(i).value);
}
max

Andrei
My Envato portfolio.

[Vince Babbra]

This works! Thanks so much to both of you. Incredible!