Number countdown with separation at every thousand units

[Xavier Gomez]

There are many many threads on counters on this forum, so many that it’s hard to find the right one…

The following should work:

// provide number to format. For instance:
tStart = inPoint;
tEnd = inPoint + 5;
vStart = 0;
vEnd = 13800;
x = linear(time, tStart, tEnd, vStart, vEnd);

// transform number to a string with 0 decimals
x = x.toFixed(0);

// provide separator
separator = ",";

// final result:
x.replace(/(\d)(?=(\d{3})+(?!\d))/g, "$1"+separator);

Xavier

[Carlos Leite]

Worked perfectly! Is there a thread where I can learn more about what the last line does?

Again, thank you very much!

[Xavier Gomez]

The last line modifies the original string using a regular expression.

Regular expressions can be from very simple to fairly complicated, and not worth the effort to learn if you plan to use very occasionnaly. Most of the time you’ll find the regular expression suited to your needs with a quick search at https://stackoverflow.com/ (in the serach, specify RegExp + javascript + what you want).

It’s actually possible to do what you wanted without a RegExp, the code is just longer but in the end it’s the same. See for instance this thread: https://forums.creativecow.net/thread/227/21144#21144 (the part that modifies the thousands is under if (commas){…}).

Xavier

[Xavier Gomez]

The last line modifies the original string using a regular expression.

Regular expressions can be from very simple to fairly complicated, and not worth the effort to learn if you plan to use very occasionnaly. Most of the time you’ll find the regular expression suited to your needs with a quick search at https://stackoverflow.com/ (in the search, specify RegExp + javascript + what you want).

It’s actually possible to do what you wanted without a RegExp, the code is just longer but in the end the result is the same. See for instance this thread: https://forums.creativecow.net/thread/227/21144#21144 (the part that modifies the thousands is under if (commas){…}).

Xavier

[Xavier Gomez]

Hmmm, i tried to edit because in the first post the link to stackoverflow didnt work… Strange result.