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need help scaling objects using 2 separate target objects
I have tried creating a target object that would create a scaling factor for all of the nulls seen in the image shown down below
I was able to create this using some code I scraped up from multiple different forums:target = thisComp.layer("Target"); dist = Math.floor( length(position, target.position) ); maxSize= 1000; minSize = 1; range = thisComp.layer("Target").effect("range")("Slider"); sensitivity = thisComp.layer("Target").effect("sensitivity")("Slider"); scle = linear(dist, range, sensitivity, maxSize, minSize);I have the code placed on all of the 44 null objects to scale in size.
my issue is, I would like to have another target object that can as well scale everything at the same time as the original. does anyone know away to create this type of transformation? -
5 Replies
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So how should the two target values interact? I mean, what’s the formula?
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They should both interact in the way of causing the green lines shown in the first image to grow and become red. The Target objects should not double the size of the green to red boundary size. To help with understanding this more, one of the targets would be on the left which would then position to the right of the screen, and vice versa for the right target.
If it helps I can attach the following project, to help with further understanding. -
Without seeing it, I’m guessing it would be something like this (totally untested, so there might be typos):
target1 = thisComp.layer("Target 1");
target2 = thisComp.layer("Target 2");
maxSize= 1000;
minSize = 1;
dist1 = Math.floor( length(position, target1.position) );
range1 = target1.effect("range")("Slider");
sensitivity1 = target1.effect("sensitivity")("Slider");
scle1 = linear(dist1, range1, sensitivity1, maxSize, minSize);
dist2 = Math.floor( length(position, target2.position) );
range2 = taarget2.effect("range")("Slider");
sensitivity2 = target2.effect("sensitivity")("Slider");
scle2 = linear(dist2, range2, sensitivity2, maxSize, minSize);
scale1/2 + scale2/2 -
Thank you, that worked!
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Thanks for solving this, Dan!
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