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Activity Forums Lighting Design Lighting A Storefront

  • Alan Lloyd

    August 30, 2010 at 2:04 pm

    Probably twenty years ago, I needed black infinity behind something. I went to my local fabric store and began browsing, and since I looked just a bit out of place there, one of the nice elderly women who ran the place came over and asked what I needed help with.

    I ended up with some leftover black “robe velour” they had sitting on one of the tables. A chunk about 8 x 12 feet. Still have it, and I used it on a shoot earlier this month.

    Total expense? $5.00 plus local sales tax.

    Might be the best fiver I’ve ever spent on anything in terms of longevity and return.

  • Todd Terry

    August 30, 2010 at 2:32 pm

    One more suggestion…

    It might seem radical, but it’s the way to 100% positively absolutely eliminate any reflections…. period

    I’ve been on a few sets where reflections would have caused big problems and it was important to have a crystal clear view on both sides of the glass (one was a big similar window, one was a car windshield, and one was the side windows on a city bus).

    They eliminated the problem by eliminating the source… and just pulled the glass.

    It might be both a bit radical and outside your budget (and time constraints) to have a glass company standing by to both pull the window and then reinstall it (not hard, but you have the knowledge of how to do it and the right tools)… but it’s the one surefire way to kill all the reflections. Although without any reflect it might look a bit unnatural.

    T2

    __________________________________
    Todd Terry
    Creative Director
    Fantastic Plastic Entertainment, Inc.
    fantasticplastic.com

  • Michael Easparam

    September 1, 2010 at 1:30 am

    A polarizer is most effective with direct sun, at a 90 degree angle. Off angle, indirect, or overcast make it less and less effective. Based on my experience, it probably would not do much in this case.

    However, as this is the simplest way, a quick trip over to the site in question with a polarizer would answer that question.

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