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JSON Data expression problem
Hi,
I’m trying to start the data graph / json tutorial. The original expression to get the country name is this:
eval(“var x=” + footage(“csvjson.json”).sourceText);
x[0].name;The problem is that i can’t get the “name” thing because in my JSON file their name goes like this:
“Country Name”: “Mexico”,
“Country Code”: “MEX”,
“Series Name”: “GDP (current US$)”,
If i type “Country Name” I get the expression error.How can I get this data witout changing all the names in my file.
* Same thing with these:
“1968 [YR1968]”: 29360000000,
“1969 [YR1969]”: 32480000000,
“1970 [YR1970]”: 35520000000,
“1971 [YR1971]”: 39200000000, -
1 Reply
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Json is funny about spaces.
I would write it like this personally.
txt = footage(“Country.json”).sourceData;
txt[“Country Name”]The above then allows for spaces.
Normally if you didn’t have spaces in Country Name like this (Country Name), it would look like this.
txt = footage(“Country.json”).sourceData;
txt.CountryNameHopefully that helps
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