Is there a way to get the current effects name?

[Xavier Gomez]

If you pickwhip the effect itself (not a property inside it), you’ll get something like
thisComp.layer(“Layer name”).effect(“Effect name”)
Then add .name to it to get:

thisComp.layer(“Layer”).effect(“Effect name”).name;

(that’s a string, the name of the effect).

Xavier

[Xavier Gomez]

Just thinking, you might actually want something else.
This will also work for a property that is an immediate child of the effect:

thisProperty.propertyGroup(1).name;

In general thisProperty is the current property, and thisProperty.propertyGroup(n) is its nth parent.
(n=0 not allowed)

[Jon Smith]

Thanks Xavier! That second response was exactly what I was looking for.