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Is there a way to determine the number of elements in an array?
Or to determine if they layer you’re using is 2d or 3d?
I’ve made a “bounce” preset expression which works pretty nicely (it can be applied to rotation or position or whatever), but it would be nice if it could be blindly applied to layers regardless of whether they’re 2D or 3D, and then have some conditional statement in the expression that works out if it needs to output 2 or 3 elements in the array at the end.
Here’s the expression (this is for Y-rotation or any one dimensional property) –
a = effect("swishAmount")("Slider"); // This defines the proportion of the sine wave used in the bounce - between 0 and 0.5 equals 0 and pi/4.
// Clamp a to 0 -> 0.5
a = Math.max(0, Math.min(0.5, a));da = a * Math.PI / 2; // "bounce" angle in radians
r1 = - da;
r2 = Math.PI + da; // start and end angles
n = 0;if (numKeys > 0) {
n = nearestKey(time).index;
if (time < key(n).time ) {
// key n is ahead of us
n--;
}
}if (numKeys > n && n > 0) {
// there's at least one key after this one, and we're not before the first key
// start & end times
t1 = key(n).time;
t2 = key(n+1).time;// start & end values
v1 = valueAtTime(t1);
v2 = valueAtTime(t2);a1 = Math.cos(r1);
a2 = Math.cos(r2); // a2 > a1, -1...1vm = (v1+v2)/2; // midpoint of the two values
a_max = vm + ((1/a2) * (v2-vm));
a_min = vm - ((1/a1) * (v1-vm)); // min and max valuestheta = ease (time, t1, t2, r1, r2);
angcos = Math.cos(theta);
res = linear(angcos, -1, 1, a_min, a_max);
} else {
// if we've gone past the last key, keep things as they were
res = value;
}res
Predictably, something like
p = transform.position;
n = p.length;
doesn’t work…. any ideas?
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2 Replies
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Try this:
if (transform.position.value.length > 2){
// 3D
}else{
// 2D
}Dan
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Amazing. Thank you Dan!
*doffs hat*
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