inPoint/outPoint Per Character Opacity

[Dan Ebberts]

Add an opacity animator, set the value to zero, add an expression selector, and one of these expressions to the selector’s Amount property:


// per-character random fade

maxDelay = .75;
fadeTime = .5

seedRandom(textIndex,true);
delay = random(maxDelay);
t = time-inPoint;
if (t < delay)
100
else
linear(t,delay,delay+fadeTime,100,0)

// random fade with flicker

maxDelay = .75;
fadeTime = .5

seedRandom(textIndex,true);
delay = random(maxDelay);
t = time-inPoint;
seedRandom(textIndex,false);
if (t < delay)
100
else
random(linear(t,delay,delay+fadeTime,100,0))


Dan

[Peter Zeet]

awesome!!

uhm… do you think is it possible to fade it out before reaching the outPoint?

thanks!!!

[Dan Ebberts]

You could do something like this:


maxDelay = .75;
fadeTime = .5

if (time < outPoint - fadeTime){
seedRandom(textIndex,true);
delay = random(maxDelay);
t = time-inPoint;
if (t < delay)
100
else
linear(t,delay,delay+fadeTime,100,0);
}else{
linear(time,outPoint-fadeTime,outPoint,0,100);
}


Dan

[Peter Zeet]

awesome! thanks!
I was thinking in a random fade out per character, but it works too!

[Peter Zeet]

actually.. do you think it’s possible to tweak the function to make the letters fade out randomly and not all the word together?

[Dan Ebberts]

Something like this, I guess:


maxDelay = .75;
fadeTime = .5

if (time < (inPoint + outPoint)/2){
seedRandom(textIndex,true);
delay = random(maxDelay);
t = time-inPoint;
if (t < delay)
100
else
linear(t,delay,delay+fadeTime,100,0);
}else{
seedRandom(textIndex+1103,true);
delay = random(maxDelay);
t = time - (outPoint-delay-fadeTime);
if (t < 0)
0
else
linear(t,0,fadeTime,0,100);
}


Dan

[Peter Zeet]

amaaazing! thanks!!!

[Jeremy Noell]

Hi Dan,

I’ve only been using expressions a short time, so I’ve been trying to solve this on my own and I just can’t quite get it.

I’m trying to do something very similar to the per-character random fade, but I would like to have each character to fade in during a longer timeline. The look I’m going for is sort of like the Wheel of Fortune puzzles that determine which player spins first. A random letter is revealed every second or so until someone buzzes in to solve it.

I have added a minDelay to the expression to have the total text fade over a timeline from 1 second to 10 seconds, but I haven’t figured out how to make the letters come up at an even pace. Any help you can give would be greatly appreciated.

Thanks
Jeremy

minDelay = 1;
maxDelay = 10;
fadeTime = .5

seedRandom(textIndex,true);
delay = random(minDelay, maxDelay);
t = time-inPoint;
if (t < delay)
100
else
linear(t,delay,delay+fadeTime,100,0)

[Dan Ebberts]

Something like this might work:


delay = .5;
fadeTime = .1;

a = [];for(i = 0; i < textTotal; i++) a.push(i);
seedRandom(index,true);
for (i = 0; i < a.length; i++){
idx = i + Math.floor(random(a.length - i));
temp = a[i];
a[i] = a[idx];
a[idx] = temp;
}
myDelay = a[textIndex-1]*delay;
t1 = inPoint + myDelay;
t2 = t1 + fadeTime;
linear(time,t1,t2,100,0)


Dan

[Jeremy Noell]

Yes, that does it! It’s also way different than I thought. I’m going to have to dig deeper into expressions.

Thanks so much!