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I have a problem about loop and array
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var layersList = app.project.activeItem.selectedLayers;
var o=[layersList];
for (i=0;i<layersList.length;i++){
checkNAME[i]=layersList[i].name;
checkNAME2[i]=layersList[i].name;
index=checkNAME[i].lastIndexOf (“-“);
if(index>=0){
checkNAME[i]= checkNAME[i].substring (0, index);
}
if(checkNAME2[i].indexOf(checkNAME[i])!==-1){
if(checkNAME2[i].indexOf(“1”,index)>-1){ <—-1
o[i]=layersList[i];
}
}
}
for(i=0;i<layersList.length;i++){
if(o[i]==null){
continue;
}
if(layersList[i].name==o[i].name){
continue;
}
alert(layersList[i].name);<—-2
}
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I try to use loop to collect layers to array of o and I want get the layer that have name like point 1 and put it and show the layer that not like 1 at 2 but it don’t show anything to me.
such as, I have layer A 01-1, A 01-2, A 01-3, B 01-1, B 01-2, B 01-3, B 01-4
It should be show A 01-2, A 01-3 and B 01-2, B 01-3, B 01-4
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1 Reply
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I tried hard to understand what did you want to do with your script. With the best of my ability, I think what you need, is to get an array of layers that has a certain string in the layer’s name.
Here’s a function you can use instead.
var proj = app.project;
var projComp = app.project.activeItem;
var selLay = projComp.selectedLayers;
function getLay(searchNameForthis){
var getLay = [];
for(var i = 0; i <= selLay.length-1; i++){
var curLay = selLay[i];
if(curLay.name.toLowerCase().indexOf(searchNameForthis) != -1){
getLay.push(curLay);
}
}
if(getLay.length > 0){
return getLay;
}else{
return 0;
}
}
alert(getLay("solid"));
You can replace the “Solid” in getLay(“Solid”); with any string that you wish to find the names by and this function will give you the layers. Hope this helps.
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